The ratio \(\gamma=C_{p, \mathrm{~m}} / C_{V, \mathrm{~m}}\) for a diatomic gaseous molecules is
The ratio \(\gamma=C_{p, \mathrm{~m}} / C_{V, \mathrm{~m}}\) for a diatomic gaseous molecules is
\(1.667\)
\(1.400\)
\(1.154\)
\(1.167\)
Solution
To find:
\(\frac{c_p}{c_v}\) for diatomic gas.
\(C_p ightarrow\) Molar specific heat capacity at constant pressure.
\(C_v ightarrow\) Molar specific heat capacity at constant volume..
\(\frac{c_p}{c_v}=1+\frac{2}{f}\)
\(f ightarrow\) degree of freedom of gas molecules.
A molecule of diatomic gas has 5 degree of freedom, i.e., \(f=5\).
\(\begin{aligned}
& \therefore \frac{C_p}{C_v}=1+\frac{2}{5}=\frac{7}{5}=1.4 \\
\therefore & \frac{C_p}{C_v} \text { for diatomic gas }=1.4
\end{aligned}\)
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