The rate of reaction between two reactants $\mathrm{A}$ and $\mathrm{B}$ decreases by a factor of 4 if the concentration of reactant $B$ is doubled. The order of this reaction iwth respect is reactant $\mathrm{B}$ is:

Question

Aicharya · Accepted Answer

Rate of reaction $=\mathrm{K}\left[\mathrm{A}_0ight]^\alpha\left[\mathrm{B}_0ight]^\beta$ $\begin{aligned} {[\mathrm{B}] } & =2\left[\mathrm{~B}_0ight] \ \frac{r_1}{r_2} & =\frac{\mathrm{K}\left[\mathrm{A}_0ight]^\alpha\left[\mathrm{B}_0ight]^\beta}{\left[\mathrm{A}_0ight]^\alpha\left[2 \mathrm{~B}_0ight]^\beta} ; \ 4 & =\left(\frac{1}{2}ight)^\beta=\beta=-2 . \end{aligned}$

The rate of reaction between two reactants $\mathrm{A}$ and $\mathrm{B}$ decreases by a factor of 4 if the…

Solution