The rate of flow of heat through a metal rod with temperature difference $40^{\circ} \mathrm{C}$ is $1600…

The rate of flow of heat through a metal rod with temperature difference $40^{\circ} \mathrm{C}$ is $1600 \mathrm{cal} / \mathrm{s}$. The thermal resistance of metal rod in ${ }^{\circ} \mathrm{C} \mathrm{s} / \mathrm{cal}$ is
  1. $0.025$
  2. $0.25$
  3. $2.5$
  4. $40$

Solution

Given: rate of flow of heat (conduction rate) $\mathrm{P}_{\text {cond }}=1600 \mathrm{cal} / \mathrm{s}$ Thermal resistance, $\begin{aligned} & \mathrm{R}_{\mathrm{T}}=\frac{\Delta \mathrm{T}}{\mathrm{P}_{\text {cond }}} \\ & \mathrm{R}_{\mathrm{T}}=\frac{40}{1600} \\ & \mathrm{R}_{\mathrm{T}}=0.025^{\circ} \mathrm{Cs} / \mathrm{cal} \end{aligned}$ ~

Asked in: MHT CET 2023 (11 May Shift 1)

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