The rate of flow of heat through a copper rod with temperature difference $28^{\circ} \mathrm{C}$ is $1400…

The rate of flow of heat through a copper rod with temperature difference $28^{\circ} \mathrm{C}$ is $1400 \mathrm{cal} \mathrm{s}^{-1}$. The thermal resistance of copper rod will be
  1. $0.05 \frac{{ }^{\circ} \mathrm{Cs}}{\mathrm{cal}}$
  2. $0.02 \frac{{ }^{\circ} \mathrm{Cs}}{\mathrm{cal}}$
  3. $5 \frac{{ }^{\circ} \mathrm{Cs}}{\mathrm{cal}}$
  4. $2 \frac{{ }^{\circ} \mathrm{Cs}}{\mathrm{cal}}$

Solution

Thermal resistance $=\frac{\text { Temp.difference }}{\text { Thermalcurrent }}=\frac{28}{1400}=0.02{ }^{\circ} \mathrm{Cs} / \mathrm{cal}$

Asked in: MHT CET 2021 (22 Sep Shift 2)

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