The rate of a first order reaction is $1.5 \times 10^{-2} \mathrm{~mol} \mathrm{~L}^{-1}$ $\min ^{-1}$ at $0…
- $0.383 \mathrm{~min}$
- $23.1 \mathrm{~min}$
- $8.73 \mathrm{~min}$
- $7.53 \mathrm{~min}$
Solution
$r=k[\mathrm{~A}]$ or $k=\frac{r}{[\mathrm{~A}]}$
$\Rightarrow k=\frac{1.5 \times 10^{-2}}{0.5}=3 \times 10^{-2}$
Further, $t_{1 / 2}=\frac{0.693}{k}=\frac{0.693}{3 \times 10^{-2}}=23.1$
Asked in: JEE-TOPICTESTS-CHEMISTRY