The rate of a certain biochemical reaction at physiological temperature T occurs 10 6 times faster with…

The rate of a certain biochemical reaction at physiological temperature T occurs 106 times faster with enzyme than without. The change in the activation energy upon adding enzyme is:
  1. -62.303RT
  2. -6RT
  3. +62.303RT
  4. +6RT

Solution

K=Ae-E/RT......(1)

106 K=Ae−EcRT…….(2)
 
On dividing eq, 2 by eq, 1

106=eE−Ec/RT
 
on taking logarithm both sides

6ln10=E−EcRT
 
2.303×6=E−EcRT
  E−Ec=2.303×(6RT)

ΔEa=Ec−E=−2.303×6RT

 

Asked in: JEE Main 2020 (08 Jan Shift 1)

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