The rate law for the reaction below is given by the expression $\mathrm{k}[\mathrm{A}][\mathrm{B}]$…

The rate law for the reaction below is given by the expression $\mathrm{k}[\mathrm{A}][\mathrm{B}]$
$\mathrm{A}+\mathrm{B} ightarrow \text { Product }$
If the concentration of $\mathrm{B}$ is increased from $0.1$ to $0.3$ mole, keeping the value of $\mathrm{A}$ at $0.1 \mathrm{~mole}$, the rate constant will be:
  1. $3 \mathrm{k}$
  2. $9 \mathrm{k}$
  3. $\mathrm{k} / 3$
  4. $\mathrm{k}$

Solution

Rate constant is independent of concentration. ,

Asked in: JEE-TOPICTESTS-CHEMISTRY

Practice more CHEMICAL KINETICS questions on Aicharya