The rate constant for a first order reaction is given by the following equation :
$lnk = 33.24 - \frac{2.0 \times 10^{4} K}{T}$
The Activation energy for the reaction is given by ${kJmol}^{- 1}$ . (In Nearest integer) (Given : $R = 8.3 J K^{- 1} {mol}^{- 1}$ )

Question

The rate constant for a first order reaction is given by the following equation :

$lnk = 33.24 - \frac{2.0 \times 10^{4} K}{T}$

The Activation energy for the reaction is given by ${kJmol}^{- 1}$ . (In Nearest integer) (Given : $R = 8.3 J K^{- 1} {mol}^{- 1}$ )

Aicharya · Accepted Answer

lnk = lnA - E A RT Given: lnk = 33 . 24 - 2 . 0 &#215; 10 4 &#160; T &#8756; on comparing E A R = 2 . 0 &#215; 10 4 &#8756; &#160; E A = 2 . 0 &#215; 10 4 &#215; R &#8658; E A = 2 . 0 &#215; 10 4 &#215; 8 . 3 &#160; J &#8658; E A = 16 . 6 &#215; 10 4 &#160; J = 166 kJ

The rate constant for a first order reaction is given by the following equation : lnk = 33 . 24 - 2 . 0…

Solution