The rank of the matrix $A=\left[\begin{array}{lll}2 & 1 & 2 \\ 1 & 0 & 1 \\ 4 & 1 & 4\end{array}\right]$ is
The rank of the matrix $A=\left[\begin{array}{lll}2 & 1 & 2 \\ 1 & 0 & 1 \\ 4 & 1 & 4\end{array}\right]$ is
- $0$
- $1$
- $2$
- $3$
Solution
Convert matrix into row echelon form.
$
\begin{aligned}
& {\left[\begin{array}{lll}
2 & 1 & 2 \\
1 & 0 & 1 \\
4 & 1 & 4
\end{array}\right] \xrightarrow{R_1 \rightarrow R_1-R_2}\left[\begin{array}{lll}
1 & 1 & 1 \\
1 & 0 & 1 \\
4 & 1 & 4
\end{array}\right]} \\
& {\left[\begin{array}{lll}
1 & 1 & 1 \\
1 & 0 & 1 \\
4 & 1 & 4
\end{array}\right] \underset{\substack{R_3 \rightarrow R_3-4 R_1}}{R_2 \rightarrow R_2-R_1}\left[\begin{array}{ccc}
1 & 1 & 1 \\
0 & -1 & 0 \\
0 & -3 & 0
\end{array}\right]} \\
& {\left[\begin{array}{lll}
1 & 1 & 1 \\
0 & -1 & 0 \\
0 & -3 & 0
\end{array}\right] \xrightarrow[R_3 \rightarrow\left(-\frac{1}{3}\right) R_3]{\stackrel{R_2 \rightarrow(-1) R_2}{\longrightarrow}}\left[\begin{array}{lll}
1 & 1 & 1 \\
0 & 1 & 0 \\
0 & 3 & 0
\end{array}\right]} \\
& {\left[\begin{array}{lll}
1 & 1 & 1 \\
0 & 1 & 0 \\
0 & 3 & 0
\end{array}\right] \xrightarrow{R_3 \rightarrow R_3-R_2}\left[\begin{array}{lll}
1 & 1 & 1 \\
0 & 1 & 0 \\
0 & 0 & 0
\end{array}\right]}
\end{aligned}
$
Number of non-zero rows is 2 .
$\therefore$ Rank of matrix is 2
Asked in: AP EAMCET 2022 (07 Jul Shift 2)
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