The rank of the matrix $A=\left[\begin{array}{lll}2 & 1 & 2 \\ 1 & 0 & 1 \\ 4 & 1 & 4\end{array}\right]$ is

The rank of the matrix $A=\left[\begin{array}{lll}2 & 1 & 2 \\ 1 & 0 & 1 \\ 4 & 1 & 4\end{array}\right]$ is
  1. $0$
  2. $1$
  3. $2$
  4. $3$

Solution

Convert matrix into row echelon form. $ \begin{aligned} & {\left[\begin{array}{lll} 2 & 1 & 2 \\ 1 & 0 & 1 \\ 4 & 1 & 4 \end{array}\right] \xrightarrow{R_1 \rightarrow R_1-R_2}\left[\begin{array}{lll} 1 & 1 & 1 \\ 1 & 0 & 1 \\ 4 & 1 & 4 \end{array}\right]} \\ & {\left[\begin{array}{lll} 1 & 1 & 1 \\ 1 & 0 & 1 \\ 4 & 1 & 4 \end{array}\right] \underset{\substack{R_3 \rightarrow R_3-4 R_1}}{R_2 \rightarrow R_2-R_1}\left[\begin{array}{ccc} 1 & 1 & 1 \\ 0 & -1 & 0 \\ 0 & -3 & 0 \end{array}\right]} \\ & {\left[\begin{array}{lll} 1 & 1 & 1 \\ 0 & -1 & 0 \\ 0 & -3 & 0 \end{array}\right] \xrightarrow[R_3 \rightarrow\left(-\frac{1}{3}\right) R_3]{\stackrel{R_2 \rightarrow(-1) R_2}{\longrightarrow}}\left[\begin{array}{lll} 1 & 1 & 1 \\ 0 & 1 & 0 \\ 0 & 3 & 0 \end{array}\right]} \\ & {\left[\begin{array}{lll} 1 & 1 & 1 \\ 0 & 1 & 0 \\ 0 & 3 & 0 \end{array}\right] \xrightarrow{R_3 \rightarrow R_3-R_2}\left[\begin{array}{lll} 1 & 1 & 1 \\ 0 & 1 & 0 \\ 0 & 0 & 0 \end{array}\right]} \end{aligned} $ Number of non-zero rows is 2 . $\therefore$ Rank of matrix is 2

Asked in: AP EAMCET 2022 (07 Jul Shift 2)

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