The radius of the nucleus of an atom whose mass number is 125 is

The radius of the nucleus of an atom whose mass number is 125 is
  1. $1 \times 10^{-15} \mathrm{~m}$
  2. $6 \times 10^{-15} \mathrm{~m}$
  3. $10 \times 10^{-15} \mathrm{~m}$
  4. $16 \times 10^{-15} \mathrm{~m}$

Solution

$\begin{aligned} & R=R_0 A^{1 / 3} \\ & =1.2 \times 10^{-15} \times(125)^{1 / 3} \\ & =1.2 \times 10^{-15} \times(5)^{3 \times \frac{1}{3}} \\ & =6 \times 10^{-15} \mathrm{~m} .\end{aligned}$

Asked in: AP EAMCET 2023 (15 May Shift 2)

Practice more Structure of Atoms and Nuclei questions on Aicharya