The radius of the innermost electron orbit of hydrogen atom is $5.3 \times 10^{-11} \mathrm{~m}$. Then the…

The radius of the innermost electron orbit of hydrogen atom is $5.3 \times 10^{-11} \mathrm{~m}$. Then the ratio of radii of the orbits of $n=2$ and $n=3$ is
  1. $9: 4$
  2. $2: 3$
  3. $4: 9$
  4. $3: 2$

Solution

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Asked in: AP EAMCET 2017 (24 Apr Shift 1)

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