The radius of the first orbit of $\mathrm{Li}^{2+}$ is $\mathrm{X} Å$. The radius of the third orbit of $\mathrm{He}^{+}$(in $Å$ ) is

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Aicharya · Accepted Answer

Radius of 1st Bohr orbit, $\mathrm{r}=\frac{0.529 \mathrm{n}^2}{\mathrm{z}} Å$ $\begin{aligned} & 	herefore \mathrm{r}_{\mathrm{He}^{+}}: \mathrm{r}_{\mathrm{Li}^{2+}}=\frac{0.529 	imes 3^2}{2}: \frac{0.529 	imes 1^2}{3}=\frac{9}{2}: \frac{1}{3} \ & 	herefore \mathrm{r}_{\mathrm{He}^{+}}=\frac{27}{2} x\end{aligned}$

The radius of the first orbit of $\mathrm{Li}^{2+}$ is $\mathrm{X} Å$. The radius of the third orbit of…

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