The radius of innermost orbit of hydrogen atom is $5.3 \times 10^{-11} \mathrm{~m}$. The radius of fourth…
The radius of innermost orbit of hydrogen atom is $5.3 \times 10^{-11} \mathrm{~m}$. The radius of fourth allowed orbit of hydrogen atom is
- $8.48 Å$
- $2 \cdot 12 Å$
- $4.77 Å$
- $0.53 Å$
Solution
$\begin{array}{ll}
& r_n \propto n^2 \\
\therefore & \frac{r_n}{r_0}=\left(\frac{n}{1}\right)^2=(4)^2=16 \\
\therefore & r_4=16 \times\left(5.3 \times 10^{-11}\right)=8.48 Å
\end{array}$
.
Asked in: MHT CET 2024 (02 May Shift 1)
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