The radius of germanium $(\mathrm{Ge})$ nuclide is measured to be twice the radius of ${ }_4^9 \mathrm{Be}$. The number of nucleons in Ge will be

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Aicharya · Accepted Answer

Using radius of a nucleus, $\mathrm{R} \propto \mathrm{A}^{1 / 3}$ Where, $A=$ number of nucleons $\begin{aligned} & 	herefore \quad \frac{R_{G e}}{R_{B e}}=\left(\frac{A_{G e}}{A_{B e}}ight)^{1 / 3} \ & 2=\left(\frac{A_{G e}}{A_{B e}}ight)^{1 / 3} 	ext { or, } 2^3=\frac{A_{G e}}{A_{B e}} \quad\left(	herefore R_{G e}=2 R_{B e}ight) \ & 2^3=\frac{A_{G e}}{9} \quad\left[	herefore A_{B e}=9ight] \ & 	herefore \quad A_{G e}=2^3 	imes 9=8 	imes 9=72 \end{aligned}$

The radius of germanium $(\mathrm{Ge})$ nuclide is measured to be twice the radius of ${ }_4^9 \mathrm{Be}$.…

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