The radius of germanium (Ge) nuclide is measured to be twice the radius of ${ }_4^9 \mathrm{Be}$. The number…
The radius of germanium (Ge) nuclide is measured to be twice the radius of ${ }_4^9 \mathrm{Be}$.
The number of nucleons in Ge are:
72
73
74
75
Solution
Nuclear radii $R=R_0 A^{1 / 3}$
Where $\quad R_0=1.2 \mathrm{fm}$
or $\quad R \propto(A)^{1 / 3}$
$\therefore \quad \frac{R_{H_e}}{R_{G_e}}=\frac{(a)^{\frac{1}{3}}}{(A)^{\frac{1}{3}}}$
or $\quad \frac{R_{H_e}}{2 R_{B^{\varepsilon}}}=\frac{(q)^{\frac{1}{3}}}{(\lambda)^{\frac{1}{3}}}$
Given $\quad R_{G e}=2 R_{B C}$
$(A)^{1 / 3}=2 \times(9)^{1 / 3}$
or $A=23 \times 9=8 \times 9=72$
$\therefore$ Number of nucleus is $\mathrm{Ge}$ is 72