The radius of a hydrogen atom is $5.29 \times 10^{-11} \mathrm{~m}$ and that of a proton is $1.5 \times…

The radius of a hydrogen atom is $5.29 \times 10^{-11} \mathrm{~m}$ and that of a proton is $1.5 \times 10^{-15} \mathrm{~m}$. The ratio of the radius of atom to the radius of proton in the scientific notation will be
  1. $3.526 \times 10^{4}$
  2. $35.266 \times 10^{3}$
  3. $3.5 \times 10^{4}$
  4. $3.5266667 \times 10^{3}$

Solution

$$
\frac{5.29 \times 10^{-11} \mathrm{~m}}{1.5 \times 10^{-15} \mathrm{~m}}=3.5 \times 10^{4}
$$
(Result will carry 2 significant digits.)

Asked in: JEE-TOPICTESTS-CHEMISTRY

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