The radii of curvature for a thin convex lens are 10 cm and 15 cm respectively. The focal length of the lens…

The radii of curvature for a thin convex lens are 10 cm and 15 cm respectively. The focal length of the lens is 12 cm. The refractive index of the lens material is
  1. 1.2
  2. 1.4
  3. 1.5
  4. 1.8

Solution

$\begin{aligned} & \frac{1}{\mathrm{f}}=(\mu-1)\left(\frac{1}{\mathrm{R}_1}-\frac{1}{\mathrm{R}_2}\right) \\ & \frac{1}{12}=(\mu-1)\left(\frac{1}{10}-\frac{1}{-15}\right) \\ & \frac{1}{12}=(\mu-1)\left(\frac{3+2}{30}\right) \\ & \mu=\frac{3}{2}\end{aligned}$

Asked in: JEE Main 2025 (03 Apr Shift 1)

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