The radiation energy density per unit wavelength at temperature $T$ is maximum at a wavelength $\lambda_0$.…
The radiation energy density per unit wavelength at temperature $T$ is maximum at a wavelength $\lambda_0$. At temperature $2 T$, it will have a maximum at a wavelength
$\frac{\lambda_0}{4}$
$2 \lambda_0$
$4 \lambda_0$
$\frac{\lambda_0}{2}$
Solution
According to Wien's displacement law, $\lambda_m T=$ constant.
$\begin{aligned} & \therefore \lambda_{\mathrm{m}} \times T=\lambda^{\prime} \times T^{\prime} \\ & \Rightarrow \lambda_0 T=\lambda^{\prime} \times 2 T \\ & \Rightarrow \lambda^{\prime}=\frac{\lambda_0}{2}\end{aligned}$