The quantum numbers of most energetic electron in Ne atom when it is in first excited state is
The quantum numbers of most energetic electron in Ne atom when it is in first excited state is
$2,1,0, \pm 1 / 2$
$3,1,1, \pm 1 / 2$
$3,0,0, \pm 1 / 2$
$3,1,0, \pm 1 / 2$
Solution
The electronic configuration of $\mathrm{Ne}$ atom is $1 \mathrm{~s}^{2} 2 \mathrm{~s}^{2} 2 \mathrm{p}^{6}$. In its first excitation state the electron from $2 \mathrm{p}$ will unpair and shift to $3 \mathrm{~s}$ where its quantum numbers will be $3,0,0$, $\pm 1 / 2$