The quadrilateral formed by the pairs of line $x y+x+y+1=0, x y+3 x+3 y+9=0$ is
- Parallelogram
- Rhombus
- Rectangle
- Square
Solution

and second pair of line $ \begin{aligned} x y+3 x+3 y+9 & =0 \\ x(y+3)+3(y+3) & =0 \\ (x+3)(y+3) & =0 \\ x=-3 \text { or } y & =-3 \end{aligned} $ $\therefore$ Quadrilateral so formed by above lines is a square Hence, option (4) is correct
Asked in: AP EAMCET 2020 (22 Sep Shift 2)