
The products in the reaction given below are ' \(\bullet\) ' denotes a free radical.

- Meso forms
- Racemic mixture
- \(d\) - and \(/\)-forms
- Cis-trans isomers
Solution

The given reaction is the chain termination step of a free radical substitution reaction. Here, the trigonal planar free radical \(\left(\mathrm{C}_2 \mathrm{H}_5-\stackrel{-}{\mathrm{C}} \mathrm{H}-\mathrm{CH}_3\right)\) gets attacked by \(\mathrm{Cl}^{-}\)with equal ease of retention and inversion in configuration. So, the final product is the equimolar mixture of \(d\) - and \(l\)-forms called racemic mixture, which is optically inactive.
Asked in: AP EAMCET 2020 (17 Sep Shift 1)
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