The products formed when diethyl ether is reacted with cold $\mathrm{HI}$ are

The products formed when diethyl ether is reacted with cold $\mathrm{HI}$ are
  1. $\mathrm{C}_2 \mathrm{H}_5 \mathrm{I}+\mathrm{C}_2 \mathrm{H}_5 \mathrm{OH}$
  2. $2 \mathrm{C}_2 \mathrm{H}_5 \mathrm{I}+\mathrm{H}_2 \mathrm{O}$
  3. $2 \mathrm{C}_2 \mathrm{H}_5 \mathrm{OH}$
  4. $\mathrm{C}_2 \mathrm{H}_5-\mathrm{O}-\mathrm{O}-\mathrm{C}_2 \mathrm{H}_5+\mathrm{H}_2 \mathrm{O}$

Solution

When diethyl ether reacts with cold $\mathrm{HI}$, ethyl alcohol and ethyl iodide are formed as final products as follows $$ \mathrm{C}_2 \mathrm{H}_5-\mathrm{O}-\mathrm{C}_2 \mathrm{H}_5+\mathrm{HI} ightarrow \mathrm{C}_2 \mathrm{H}_5 \mathrm{OH}+\mathrm{C}_2 \mathrm{H}_5 \mathrm{I} $$ ~

Asked in: JEE-TOPICTESTS-CHEMISTRY

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