The product of the distinct $(2 n)$ th roots of $1+i \sqrt{3}$ is equal to :
The product of the distinct $(2 n)$ th roots of $1+i \sqrt{3}$ is equal to :
- 0
- $-1-i \sqrt{3}$
- $1+i \sqrt{3}$
- $-1+i \sqrt{3}$
Solution
Product of the distinct $(2 n)^{\text {th }}$ roots of $1+i \sqrt{3}$ $=-1-i \sqrt{3}$
Asked in: AP EAMCET 2006
Practice more Complex Number questions on Aicharya