$\text {In the following reaction }$ $\mathrm{C}_6 \mathrm{H}_5 \mathrm{CH}_2 \mathrm{Br} \frac{1 .…

$\text {In the following reaction }$ $\mathrm{C}_6 \mathrm{H}_5 \mathrm{CH}_2 \mathrm{Br} \frac{1 . \mathrm{Mg} \text {, Ether }}{2 . \mathrm{H}_3 \mathrm{O}^{+}} \mathrm{X}$ the product ' $X$ ' is
  1. $\mathrm{C}_6 \mathrm{H}_5 \mathrm{CH}_2 \mathrm{OCH}_2 \mathrm{C}_6 \mathrm{H}_5$
  2. $\mathrm{C}_6 \mathrm{H}_5 \mathrm{CH}_2 \mathrm{OH}$
  3. $\mathrm{C}_6 \mathrm{H}_5 \mathrm{CH}_3$
  4. $\mathrm{C}_6 \mathrm{H}_5 \mathrm{CH}_2 \mathrm{CH}_2 \mathrm{C}_6 \mathrm{H}_5$

Asked in: NEET 2010 (Mains)

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