The probability that the person who undergoes certain operation will survive is $0 \cdot 2 .$ If 5 patients…
The probability that the person who undergoes certain operation will survive is $0 \cdot 2 .$
If 5 patients undergo similar operations, then the probability that exactly four will survive is
$0.0042$
$0.0084$
$0 \cdot 0032$
$0 \cdot 0064$
Solution
Since there are 5 patients, n = 5
P(Pprobability of patient survive) = 0.2
$\begin{aligned} \quad & p-0.2 \Rightarrow q=1-p=1-0.2=08 \\ & P(x=4)={ }^{5} C_{4}(0.2)^{4}(0.8)^{1}=5 \times 0.0016 \times 0.8=0.0064 \end{aligned}$