The probability, that in a randomly selected 3 -digit number at least two digits are odd, is

Total No of 3-digit Number $=900$

Case -1 When there are $2$ odd digit and $1$ even digit

(i) Even odd odd $=4\times 5\times 5=100$

{As $0$ cannot come at $1^{\mathrm{st}}$ place}

(ii) Odd even odd $=5\times 5\times 5=125$

(iii) Odd odd even $=5\times 5\times 5=125$

Case-2

All $3$ odd digit $=5\times 5\times 5=125$

So total number of selecting $3$-digit number having atleast $2$ odd digit will be addition of both cases which is$=100+125+125+125=475$

So probability $=\frac{475}{900}=\frac{19}{36}$