The probability that at least one of the events $A$ and $B$ occurs is 0.6 . If $A$ and $B$ occur simultaneously with probability 0.2 , then $P\left(A^{\prime}\right)+P\left(B^{\prime}\right)$ is equal to

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Aicharya · Accepted Answer

$\begin{aligned} & P(A \cup B)=0.6 	ext { and } P(A \cap B)=0.2 \ & 	ext { Now } P\left(A^{\prime}ight)+P\left(B^{\prime}ight)=1-P(A)+1-P(B) \ & =2-\{P(A)+P(B)\} \ & =2-\{P(A \cup B)+P(A \cap B)\} \ & =2-\{0.6+0.2\} \ & =2-0.8 \ & =1.2\end{aligned}$

The probability that at least one of the events $A$ and $B$ occurs is 0.6 . If $A$ and $B$ occur…

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