The probability that a number selected at random from the set of numbers $(1,2,3, \ldots, 100)$ is a cube, is

The probability that a number selected at random from the set of numbers $(1,2,3, \ldots, 100)$ is a cube, is
  1. $\frac{1}{25}$
  2. $\frac{2}{25}$
  3. $\frac{3}{25}$
  4. $\frac{4}{25}$

Solution

$n(S)=100$ The set of cube numbers $A=\left\{1^3, 2^3, 3^3, 4^3\right\}$ Total number in favour $n(A)=4$ Required probability $=\frac{n(A)}{n(S)}=\frac{4}{100}=\frac{1}{25}$

Asked in: AP EAMCET 2001

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