The probability of getting a sum 9 when two dice are thrown is
The probability of getting a sum 9 when two dice are thrown is
$\frac{1}{6}$
$\frac{1}{8}$
$\frac{1}{9}$
$\frac{1}{12}$
Solution
When two dice are rolled together, then total outcomes are 36 and sample space is
$\begin{aligned} & {[(1,1),(1,2),(1,3),(1,4),(1,5)(1,6),} \\ & (2,1),(2,2),(2,3),(2,4),(2,5),(2,6), \\ & (3,1),(3,2),(3,3),(3,4),(3,5),(3,6), \\ & (4,1),(4,2),(4,3),(4,4),(4,5),(4,6), \\ & (5,1),(5,2),(5,3),(5,4),(5,5),(5,6), \\ & (6,1),(6,2),(6,3),(6,4),(6,5),(6,6)]\end{aligned}$
So, pairs with sum 9 are $(3,6)(4,5),(5,4),(6,3)$
i.e total 4 pairs.
Total outcomes $=36$
Favourable outcomes $=4$
Probability of getting the sum of 9
$=\frac{4}{36}=\frac{1}{9}$