The probability of an impossible event is $a$ and that of a sure event is $b$. Then $a+b = $

The probability of an impossible event is $a$ and that of a sure event is $b$. Then $a+b = $
  1. $0$
  2. $\dfrac{1}{2}$
  3. $1$
  4. $2$

Solution

$a = 0$ (impossible event), $b = 1$ (sure event). So $a+b = 0+1 = 1$.

Asked in: IMO

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