The probability distribution of random variable X is given by: X 1 2 3 4 5 P ( X ) K 2 K 2 K 3 K K Let p = P…

The probability distribution of random variable X is given by:

X 1 2 3 4 5
P(X) K 2K 2K 3K K

Let p=P(1<X<4X<3). If 5p=λK, then λ is equal to

Solution

ΣP(X)=1
K+2K+2K+3K+K=1
K=19
P=P(1<X<4X<3)=P(X=2)P(X<3)
P=2K9KK9K+2k9K=23
5P=λK
5×23=λ×19λ=30

Asked in: JEE Main 2021 (27 Aug Shift 2)

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