The principal value of $\sin ^{-1}\left(-\frac{1}{2}\right)$ is

The principal value of $\sin ^{-1}\left(-\frac{1}{2}\right)$ is
  1. $\frac{\pi}{3}$
  2. $\frac{\pi}{6}$
  3. $-\frac{\pi}{3}$
  4. $-\frac{\pi}{6}$

Solution

$\sin ^{-1}\left(-\frac{1}{2}\right)=-\sin ^{-1} \frac{1}{2}=\frac{-\pi}{6}$

Asked in: MHT CET 2020 (15 Oct Shift 1)

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