The principal organic product formed in the reaction,…

The principal organic product formed in the reaction,
$\mathrm{CH}_{2}=\mathrm{CH}\left(\mathrm{CH}_{2}ight)_{8} \mathrm{COOH}+\mathrm{HBr} \stackrel{\text { peroxide }}{\longrightarrow}$ is
  1. $\mathrm{CH}_{3} \mathrm{CHBr}\left(\mathrm{CH}_{2}ight)_{8} \mathrm{COOH}$
  2. $\mathrm{CH}_{2}=\mathrm{CH}\left(\mathrm{CH}_{2}ight)_{8} \mathrm{COBr}$
  3. $\mathrm{CH}_{2} \mathrm{BrCH}_{2}\left(\mathrm{CH}_{2}ight)_{8} \mathrm{COOH}$
  4. $\mathrm{CH}_{2}=\mathrm{CH}\left(\mathrm{CH}_{2}ight)_{7} \mathrm{CHBrCOOH}$

Solution

A molecule of $\mathrm{HBr}$ is added to $\mathrm{C}=\mathrm{C}$ double bond. $\mathrm{Br}$ is added to less substituted terminal carbon atom. (The anti markonikov's addition of HBr to unsymmetrical alkenes in presence of peroxides)

Asked in: JEE-TOPICTESTS-CHEMISTRY

Practice more HYDROCARBONS questions on Aicharya