The pressure exerted by a mixture of 3 . 2   g of methane and 4 . 4   g of CO 2 contained in a 9…

The pressure exerted by methane is $\mathrm{P}=\frac{\mathrm{nRT}}{\mathrm{V}}$

$$\begin{gathered} =\frac{0.2\times 8.314\times 300}{9\times {10}^{-3}} \\ =5.54\times {10}^4 \mathrm{Pa} \end{gathered}$$

The pressure exerted by ${\mathrm{CO}}_2$​ is ${\mathrm{P}}^{\text{'}}=\frac{\mathrm{n}\text{'}\mathrm{RT}}{\mathrm{V}}$

$$\begin{gathered} =\frac{0.1\times 8.314\times 300}{9\times {10}^{-3}} \\ =2.77\times {10}^4 \mathrm{Pa} \end{gathered}$$

The total pressure is $\mathrm{P}+{\mathrm{P}}^{\text{'}}$.

$$\begin{gathered} =\left(5.54\times {10}^4 \mathrm{Pa}\right)+\left(2.77\times {10}^4 \mathrm{Pa}\right) \\ =8.31\times {10}^4 \mathrm{Pa} \end{gathered}$$