The power utilised when a force of \((2 \hat{\mathbf{i}}+3 \hat{\mathbf{j}}+4 \hat{\mathbf{k}}) \mathrm{N}\)…

The power utilised when a force of \((2 \hat{\mathbf{i}}+3 \hat{\mathbf{j}}+4 \hat{\mathbf{k}}) \mathrm{N}\) acts on a body for \(4 \mathrm{~s}\), producing a displacement of \((3 \hat{\mathbf{i}}+4 \hat{\mathbf{j}}+5 \hat{\mathbf{k}}) \mathrm{m}\), is
  1. \(9.5 \mathrm{~W}\)
  2. \(7.5 \mathrm{~W}\)
  3. \(6.5 \mathrm{~W}\)
  4. \(4.5 \mathrm{~W}\)

Solution

Force, \(\mathbf{F}=2 \hat{\mathbf{i}}+3 \hat{\mathbf{j}}+4 \hat{\mathbf{k}}\) Displacement, \(\mathbf{s}=3 \hat{\mathbf{i}}+4 \hat{\mathbf{j}}+5 \hat{\mathbf{k}}\) \(\begin{aligned} & \therefore \text { Velocity } =\frac{\text { Displacement }}{\text { Time }} \\ & \Rightarrow v =\frac{\mathbf{s}}{t}=\frac{1}{4}(3 \hat{\mathbf{i}}+4 \hat{\mathbf{j}}+5 \hat{\mathbf{k}}) \end{aligned}\) \(\therefore\) Power utilised is given as \(\begin{aligned} P & =\mathbf{F} \cdot \mathbf{v} \\ & =(2 \hat{\mathbf{i}}+3 \hat{\mathbf{j}}+4 \hat{\mathbf{k}}) \cdot \frac{1}{4}(3 \hat{\mathbf{i}}+4 \hat{\mathbf{j}}+5 \hat{\mathbf{k}}) \\ & =2 \times \frac{3}{4}+3 \times \frac{4}{4}+4 \times \frac{5}{4} \\ & =1.5+3+5=9.5 \mathrm{~W} \end{aligned}\)

Asked in: AP EAMCET 2020 (21 Sep Shift 1)

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