The potential energy function (in J ) of a particle in a region of space is given as U = 2 x 2 + 3 y 3 + 2 z…

The potential energy function (in J ) of a particle in a region of space is given as U=2x2+3y3+2z. Here x, y and z are in meter. The magnitude of x - component of force (in N ) acting on the particle at point P(1, 2, 3) m is:
  1. 2
  2. 6
  3. 4
  4. 8

Solution

Given U=2x2+3y3+2z

The expression for the x-component of the force can be calculated as follows: 

Fx=-Ux=-4x

Hence, at the point 1, 2, 3 m, the value of the force is given by

Fx=-4×1 N=4 N

Asked in: JEE Main 2024 (29 Jan Shift 1)

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