
The potential difference $\left(\mathrm{V}_{\mathrm{A}}-\mathrm{V}_{\mathrm{B}}\right)$ between the points '…

- -3 V
- 3 V
- 6 V
- 9 V
Solution

By Kirchhoff's voltage law, $V_A-(2 \times 2)-(3)-(2 \times 1)-V_B=0$ $\begin{array}{ll}\therefore & \mathrm{V}_{\mathrm{A}}-4-3-2-\mathrm{V}_{\mathrm{B}}=0 \\ \therefore & \mathrm{~V}_{\mathrm{A}}-\mathrm{V}_{\mathrm{B}}=+9 \mathrm{~V}\end{array}$
Asked in: MHT CET 2024 (10 May Shift 2)