The potential difference $\left(V_A-V_B\right)$ between the points A and B in the given part of the circuit
- -13 V
- 13 V
- -23 V
- 23 V
Solution
By Kirchhoff's voltage law, $\begin{array}{ll} & \mathrm{V}_{\mathrm{A}}-(4 \times 3)-(5)-(2 \times 3)-\mathrm{V}_{\mathrm{B}}=0 \\ \therefore \quad & \mathrm{~V}_{\mathrm{A}}-12-5-6-\mathrm{V}_{\mathrm{B}}=0 \\ \therefore \quad & \mathrm{~V}_{\mathrm{A}}-\mathrm{V}_{\mathrm{B}}=+23 \mathrm{~V} \end{array}$
Asked in: MHT CET 2024 (16 May Shift 1)