The position of a particle related to time is given by x = ( 5 t 2 - 4 t + 5 )   m . The magnitude of…

The position of a particle related to time is given by x=(5t2-4t+5) m. The magnitude of velocity of the particle at t=2 s will be :
  1. 06 m s-1
  2. 14 m s-1
  3. 10 m s-1
  4. 16 m s-1

Solution

It is given that

x=5t2-4t+5

The velocity is given by 

v=dxdt=d(5t2-4t+5)dt=10t -4 

At t=2 s,

v=10(2)-4=16 m s-1

Asked in: JEE Main 2023 (15 Apr Shift 1)

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