The position of a particle moving on $x$-axis is given by $x(t)=A \sin t+B \cos ^2 t+C t^2+D$, where $t$ is time. The dimension of $\frac{A B C}{D}$ is

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Aicharya · Accepted Answer

$\begin{aligned} & 	ext { Dimension }[\mathrm{x}(\mathrm{t})]=[\mathrm{L}] \ & {[\mathrm{A}]=[\mathrm{L}]} \ & {[\mathrm{B}]=[\mathrm{L}]} \ & {[\mathrm{C}]=\left[\mathrm{LT}^{-2}ight]} \ & {[\mathrm{D}]=[\mathrm{L}]} \ & {\left[\frac{\mathrm{ABC}}{\mathrm{D}}ight]=\left[\frac{\mathrm{L} 	imes \mathrm{L} 	imes \mathrm{LT}^{-2}}{\mathrm{~L}}ight]=\left[\mathrm{L}^2 \mathrm{~T}^{-2}ight]}\end{aligned}$

The position of a particle moving on $x$-axis is given by $x(t)=A \sin t+B \cos ^2 t+C t^2+D$, where $t$ is…

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