The polydispersity index of a polymer containing 10 molecules with molecular mass $1.0 \times 10^4$ and 10…

The polydispersity index of a polymer containing 10 molecules with molecular mass $1.0 \times 10^4$ and 10 molecules with molecular mass $1.0 \times 10^5$ is approximately.
  1. 1.67
  2. 0.59
  3. 1.55
  4. 0.83

Solution

The PDI (polydispersity index) $=\frac{M_w}{M_n}=1.67$ $M_w=$ Weight average molecular weight. $M_n=$ Number average molecular weight. $ \begin{aligned} & M_n=\frac{N_1 M_1+N_2 M_2}{N_1+N_2}=55,000 \\ & M_w=\frac{N_1 M_1^2+N_2 M_2^2}{N_1 M_1+N_2 M_2}=91818 \end{aligned} $

Asked in: AP EAMCET 2018 (22 Apr Shift 2)

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