The points where the circle x 2 + y 2 - 3 x - 4 y + 2 = 0 cuts the x -axis are

The points where the circle x2+y2-3x-4y+2=0 cuts the x-axis are
  1. (1,2)&(2,0)
  2. (2,0)&(3,0)
  3. (0,2)&(0,1)
  4. (1,0)&(2,0)

Solution

Given that: x2+y2-3x-4y+2=0

Circle cuts x-axis, So put y=0

x2-3x+2=0

⇒x-1x-2=0

⇒x=1,2

Points are 1,0 & 2,0.

Asked in: AP EAMCET 2021 (20 Aug Shift 2)

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