The point of intersection of the lines represented by $\mathbf{r}=(\hat{\mathbf{i}}+2…

The point of intersection of the lines represented by $\mathbf{r}=(\hat{\mathbf{i}}+2 \hat{\mathbf{j}}-\hat{\mathbf{k}})+\lambda(2 \hat{\mathbf{i}}+3 \hat{\mathbf{j}}+4 \hat{\mathbf{k}})$ and $\mathbf{r}=(-\hat{\mathbf{i}}-3 \hat{\mathbf{j}}+7 \hat{\mathbf{k}})+\mu(\hat{\mathbf{i}}+2 \hat{\mathbf{j}}-\hat{\mathbf{k}})$ is
  1. $3 \hat{\mathbf{i}}+5 \hat{\mathbf{j}}+3 \hat{\mathbf{k}}$
  2. $5 \hat{\mathbf{i}}+8 \hat{\mathbf{j}}+7 \hat{\mathbf{k}}$
  3. $-\hat{\mathbf{i}}-\hat{\mathbf{j}}-5 \hat{\mathbf{k}}$
  4. $-3 \hat{\mathbf{i}}-4 \hat{\mathbf{j}}-9 \hat{\mathbf{k}}$

Solution

Let point $P$ is the point of intersection of given lines $\mathbf{r}=(\hat{\mathbf{i}}+2 \hat{\mathbf{j}}-\hat{\mathbf{k}})+\lambda(2 \hat{\mathbf{i}}+3 \hat{\mathbf{j}}+4 \hat{\mathbf{k}})$ and $\mathbf{r}=(-\hat{\mathbf{i}}-3 \hat{\mathbf{j}}+7 \hat{\mathbf{k}})+\mu(\hat{\mathbf{i}}+2 \hat{\mathbf{j}}-\hat{\mathbf{k}})$ So, for point $P$,
From Eqs. (i) and (iii), we get $\lambda=1$ and $\mu=4$, which satisfy the Eq. (ii), so required point of intersection $P$ is $3 \hat{\mathbf{i}}+5 \hat{\mathbf{j}}+3 \hat{\mathbf{k}}$. Hence, option (a) is correct.

Asked in: AP EAMCET 2019 (20 Apr Shift 2)

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