The point of concurrence of the polars of the variable point $(2 t, t-4), t \in \mathbb{R}$ with respect to…

The point of concurrence of the polars of the variable point $(2 t, t-4), t \in \mathbb{R}$ with respect to the circle $x^2+y^2-4 x-6 y+1=0$ is
  1. $(1,3)$
  2. $(1,-3)$
  3. $(-3,1)$
  4. $(3,1)$

Solution

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Asked in: AP EAMCET 2017 (24 Apr Shift 1)

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