The point $P(a, b)$ lies on the straight line $3 x+2 y=13$ and the point $Q(b, a)$ lies on the straight line…

The point $P(a, b)$ lies on the straight line $3 x+2 y=13$ and the point $Q(b, a)$ lies on the straight line $4 x-y=5$. Then the equation of the line $P Q$ is
  1. $x+y=7$
  2. $x+y=5$
  3. $x+y=2$
  4. $x+y=21$

Solution

No solution. Refer to answer key.

Asked in: AP EAMCET 2017 (25 Apr Shift 2)

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