The point dividing the join of $(3,-2,1)$ and $(-2,3,11)$ in the ratio $2: 3$ is

The point dividing the join of $(3,-2,1)$ and $(-2,3,11)$ in the ratio $2: 3$ is
  1. $(1,1,4)$
  2. $(1,0,5)$
  3. $(2,3,5)$
  4. $(0,6,-1)$

Solution

Let require point is $P$, then by section formula the coordinate of point $P$ are
$\Rightarrow P\left(\frac{m x_2+n x_1}{m+n}, \frac{m y_2+n y_1}{m+n}, \frac{m z_2+n z_1}{m+n}\right)$ $\Rightarrow \quad P\left(\frac{-4+9}{2+3}, \frac{6-6}{2+3}, \frac{22+3}{2+3}\right)$ $\Rightarrow \quad P\left(\frac{5}{5}, \frac{0}{5}, \frac{25}{5}\right)$ $\Rightarrow \quad P(1,0,5)$

Asked in: AP EAMCET 2010

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