The plane of a dip circle is set in the geographic meridian and the apparent dip is $\delta_1$. It is then…

The plane of a dip circle is set in the geographic meridian and the apparent dip is $\delta_1$. It is then set in a vertical plane perpendicular to the geographic meridian. The apparent dip angle is $\delta_2$. The declination $\theta$ at the place is
  1. $\theta=\operatorname{Tan}^{-1}\left(\tan \delta_1 \cdot \tan \delta_2\right)$
  2. $\theta=\operatorname{Tan}^{-1}\left(\tan \delta_1+\tan \delta_2\right)$
  3. $\theta=\operatorname{Tan}^{-1}\left(\frac{\tan \delta_1}{\tan \delta_2}\right)$
  4. $\theta=\operatorname{Tan}^{-1}\left(\tan \delta_1-\tan \delta_2\right)$

Solution

No solution. Refer to answer key.

Asked in: AP EAMCET 2020 (07 Oct Special)

Practice more Magnetic Properties of Matter questions on Aicharya