The p H of a 0.02   M N H 4 C l solution will be [Given: K b N H 4 O H = 10 - 5 and log ⁡ 2 = 0.301 ]

Question

The p H of a 0.02 &#160; M N H 4 C l solution will be [Given: K b N H 4 O H = 10 - 5 and log &#8289; 2 = 0.301 ]

Aicharya · Accepted Answer

N H 4 C l is a salt of a strong acid and a weak base. pH = 1 2 pK w - pK b - logC = 1 2 14 - 5 - log &#8289; 2 &#215; 10 - 2 = 1 2 9 - log &#8289; 2 - log &#8289; 10 - 2 = 1 2 9 - log &#8289; 2 + 2 = 10.7 2 = 5.35

The p H of a 0.02   M N H 4 C l solution will be [Given: K b N H 4 O H = 10 - 5 and log ⁡ 2 = 0…

Solution

The p H of a 0.02 &#160; M N H 4 C l solution will be [Given: K b N H 4 O H = 10 - 5 and log &#8289; 2 = 0…

Solution

The p H of a 0.02 M N H 4 C l solution will be [Given: K b N H 4 O H = 10 - 5 and log ⁡ 2 = 0…