The perpendicular distance of the origin from the plane $2 x+y-2 z-18=0$ is

The perpendicular distance of the origin from the plane $2 x+y-2 z-18=0$ is
  1. 18 units
  2. 9 units
  3. 6 units
  4. 4 units

Solution

$\begin{aligned} \text { Required distance } & =\left|\frac{2(0)+(0)-2(0)-18}{\sqrt{4+1+4}}\right| \\ & =6 \text { units }\end{aligned}$

Asked in: MHT CET 2024 (11 May Shift 1)

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