The perpendicular bisector of the line segment joining $P(1,4)$ and $Q(k, 3)$ has $y$-intercept - 4. Then a…

The perpendicular bisector of the line segment joining $P(1,4)$ and $Q(k, 3)$ has $y$-intercept - 4. Then a possible value of $k$ is
  1. 1
  2. 2
  3. $-2$
  4. $-4$

Solution

Slope of bisector $=k-1$ Middle point $=\left(\frac{\mathrm{k}+1}{2}, \frac{7}{2}\right)$ Equation of bisector is $y-\frac{7}{2}=(k-1)\left(x-\frac{(k+1)}{2}\right)$ Put $\mathrm{x}=0$ and $\mathrm{y}=-4$ $ \Rightarrow k=\pm 4 $

Asked in: JEE Main 2008

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